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31144430101315 = 541903148650121
BaseRepresentation
bin1110001010011011000001…
…01100010110001101000011
311002021101012212211112020211
413011031200230112031003
513040232243101220230
6150123315332014551
76363053003632636
oct705154054261503
9132241185745224
1031144430101315
119a18307949843
1235abbba761457
13144bba403bbab
14799581533c1d
1539021114442a
hex1c5360b16343

31144430101315 has 8 divisors (see below), whose sum is σ = 37374208273728. Its totient is φ = 24914949312960.

The previous prime is 31144430101249. The next prime is 31144430101357. The reversal of 31144430101315 is 51310103444113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 31144430101315 - 29 = 31144430100803 is a prime.

It is a super-4 number, since 4×311444301013154 (a number of 55 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74115546 + ... + 74534575.

It is an arithmetic number, because the mean of its divisors is an integer number (4671776034216).

Almost surely, 231144430101315 is an apocalyptic number.

31144430101315 is a deficient number, since it is larger than the sum of its proper divisors (6229778172413).

31144430101315 is a wasteful number, since it uses less digits than its factorization.

31144430101315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 148692029.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 31144430101315 its reverse (51310103444113), we get a palindrome (82454533545428).

The spelling of 31144430101315 in words is "thirty-one trillion, one hundred forty-four billion, four hundred thirty million, one hundred one thousand, three hundred fifteen".

Divisors: 1 5 41903 209515 148650121 743250605 6228886020263 31144430101315