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3114530345051 = 4372430938257
BaseRepresentation
bin101101010100101000011…
…110011001000001011011
3102000202010222022121220122
4231110220132121001123
5402012024232020201
610342443454143455
7441005652061436
oct55245036310133
912022128277818
103114530345051
11aa0957203104
12423749ab1b8b
13197911799648
14aaa5ba4481d
1556039420e1b
hex2d52879905b

3114530345051 has 4 divisors (see below), whose sum is σ = 3186961283352. Its totient is φ = 3042099406752.

The previous prime is 3114530344973. The next prime is 3114530345053. The reversal of 3114530345051 is 1505430354113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3114530345051 - 230 = 3113456603227 is a prime.

It is a super-2 number, since 2×31145303450512 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3114530345053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36215469086 + ... + 36215469171.

It is an arithmetic number, because the mean of its divisors is an integer number (796740320838).

Almost surely, 23114530345051 is an apocalyptic number.

3114530345051 is a deficient number, since it is larger than the sum of its proper divisors (72430938301).

3114530345051 is an equidigital number, since it uses as much as digits as its factorization.

3114530345051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72430938300.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 3114530345051 its reverse (1505430354113), we get a palindrome (4619960699164).

The spelling of 3114530345051 in words is "three trillion, one hundred fourteen billion, five hundred thirty million, three hundred forty-five thousand, fifty-one".

Divisors: 1 43 72430938257 3114530345051