Search a number
-
+
3114554113 = 11436584681
BaseRepresentation
bin1011100110100100…
…0101001100000001
322001001120202001001
42321221011030001
522334311212423
61233015412001
7140116162456
oct27151051401
98031522031
103114554113
1113590a2670
1272b084001
133a8352738
1421790582d
15133670cad
hexb9a45301

3114554113 has 8 divisors (see below), whose sum is σ = 3476712096. Its totient is φ = 2765565600.

The previous prime is 3114554033. The next prime is 3114554129.

3114554113 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3114554113 - 213 = 3114545921 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3114554153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3291868 + ... + 3292813.

It is an arithmetic number, because the mean of its divisors is an integer number (434589012).

Almost surely, 23114554113 is an apocalyptic number.

It is an amenable number.

3114554113 is a deficient number, since it is larger than the sum of its proper divisors (362157983).

3114554113 is a wasteful number, since it uses less digits than its factorization.

3114554113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6584735.

The product of its digits is 3600, while the sum is 28.

The square root of 3114554113 is about 55808.1903756071. The cubic root of 3114554113 is about 1460.3780394982.

It can be divided in two parts, 31145 and 54113, that added together give a palindrome (85258).

The spelling of 3114554113 in words is "three billion, one hundred fourteen million, five hundred fifty-four thousand, one hundred thirteen".

Divisors: 1 11 43 473 6584681 72431491 283141283 3114554113