3114840484113 has 16 divisors (see below), whose sum is σ = 4266201169920. Its totient is φ = 2020042008576.

The previous prime is 3114840484111. The next prime is 3114840484157.

3114840484113 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 3114840484113 - 2¹ = 3114840484111 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (3114840484111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2172720 + ... + 3309137.

It is an arithmetic number, because the mean of its divisors is an integer number (266637573120).

Almost surely, 2^{3114840484113} is an apocalyptic number.

It is an amenable number.

3114840484113 is a deficient number, since it is larger than the sum of its proper divisors (1151360685807).

3114840484113 is a wasteful number, since it uses less digits than its factorization.

3114840484113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5487016.

The product of its (nonzero) digits is 147456, while the sum is 42.

It can be divided in two parts, 3114840 and 484113, that added together give a palindrome (3598953).

The spelling of 3114840484113 in words is "three trillion, one hundred fourteen billion, eight hundred forty million, four hundred eighty-four thousand, one hundred thirteen".