3115050121 has 4 divisors (see below), whose sum is σ = 3135679744. Its totient is φ = 3094420500.

The previous prime is 3115050119. The next prime is 3115050137. The reversal of 3115050121 is 1210505113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1210505113 = 1741 ⋅695293.

It is a cyclic number.

It is not a de Polignac number, because 3115050121 - 2¹ = 3115050119 is a prime.

It is a super-2 number, since 2×3115050121² = 19407074512684229282, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3115050721) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10314585 + ... + 10314886.

It is an arithmetic number, because the mean of its divisors is an integer number (783919936).

Almost surely, 2^3115050121 is an apocalyptic number.

It is an amenable number.

3115050121 is a deficient number, since it is larger than the sum of its proper divisors (20629623).

3115050121 is a wasteful number, since it uses less digits than its factorization.

3115050121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20629622.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 3115050121 is about 55812.6340625490. The cubic root of 3115050121 is about 1460.4555595022.

Adding to 3115050121 its reverse (1210505113), we get a palindrome (4325555234).

The spelling of 3115050121 in words is "three billion, one hundred fifteen million, fifty thousand, one hundred twenty-one".