Base | Representation |
---|---|
bin | 101101010101001100010… |
… | …011011011111110101011 |
3 | 102000210200212102002111011 |
4 | 231111030103123332223 |
5 | 402014242123001410 |
6 | 10343023250044351 |
7 | 441026601314665 |
oct | 55251423337653 |
9 | 12023625362434 |
10 | 3115131453355 |
11 | aa1135548729 |
12 | 4238972796b7 |
13 | 1979a919282c |
14 | aaab77d9535 |
15 | 560720ac18a |
hex | 2d54c4dbfab |
3115131453355 has 4 divisors (see below), whose sum is σ = 3738157744032. Its totient is φ = 2492105162680.
The previous prime is 3115131453341. The next prime is 3115131453433. The reversal of 3115131453355 is 5533541315113.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 3115131453355 - 213 = 3115131445163 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 311513145331 + ... + 311513145340.
It is an arithmetic number, because the mean of its divisors is an integer number (934539436008).
Almost surely, 23115131453355 is an apocalyptic number.
3115131453355 is a deficient number, since it is larger than the sum of its proper divisors (623026290677).
3115131453355 is an equidigital number, since it uses as much as digits as its factorization.
3115131453355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 623026290676.
The product of its digits is 202500, while the sum is 40.
Adding to 3115131453355 its reverse (5533541315113), we get a palindrome (8648672768468).
The spelling of 3115131453355 in words is "three trillion, one hundred fifteen billion, one hundred thirty-one million, four hundred fifty-three thousand, three hundred fifty-five".
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