311540650113331 has 4 divisors (see below), whose sum is σ = 312026672969064. Its totient is φ = 311054627257600.

The previous prime is 311540650113271. The next prime is 311540650113367. The reversal of 311540650113331 is 133311056045113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 311540650113331 - 2²¹ = 311540648016179 is a prime.

It is a super-3 number, since 3×311540650113331³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311540650110331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243011426905 + ... + 243011428186.

It is an arithmetic number, because the mean of its divisors is an integer number (78006668242266).

Almost surely, 2^{311540650113331} is an apocalyptic number.

311540650113331 is a deficient number, since it is larger than the sum of its proper divisors (486022855733).

311540650113331 is an equidigital number, since it uses as much as digits as its factorization.

311540650113331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 486022855732.

The product of its (nonzero) digits is 48600, while the sum is 37.

The spelling of 311540650113331 in words is "three hundred eleven trillion, five hundred forty billion, six hundred fifty million, one hundred thirteen thousand, three hundred thirty-one".