Base | Representation |
---|---|
bin | 101101010110011111000… |
… | …101010100101000001001 |
3 | 102000221021122200220000001 |
4 | 231112133011110220021 |
5 | 402030113141342103 |
6 | 10343413141043001 |
7 | 441106164100144 |
oct | 55263705245011 |
9 | 12027248626001 |
10 | 3116520262153 |
11 | aa17884932a1 |
12 | 4240043b6461 |
13 | 197b6ab2349c |
14 | aabaa03705b |
15 | 56103e9101d |
hex | 2d59f154a09 |
3116520262153 has 4 divisors (see below), whose sum is σ = 3120148342480. Its totient is φ = 3112892181828.
The previous prime is 3116520262129. The next prime is 3116520262181. The reversal of 3116520262153 is 3512620256113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3116520262153 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3116520262183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1814038875 + ... + 1814040592.
It is an arithmetic number, because the mean of its divisors is an integer number (780037085620).
Almost surely, 23116520262153 is an apocalyptic number.
It is an amenable number.
3116520262153 is a deficient number, since it is larger than the sum of its proper divisors (3628080327).
3116520262153 is an equidigital number, since it uses as much as digits as its factorization.
3116520262153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3628080326.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 3116520262153 in words is "three trillion, one hundred sixteen billion, five hundred twenty million, two hundred sixty-two thousand, one hundred fifty-three".
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