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312000011313 = 3195473684409
BaseRepresentation
bin1001000101001001010…
…01100101110000110001
31002211022211001202121120
410202210221211300301
520102434000330223
6355155243012453
731353436224144
oct4424451456061
91084284052546
10312000011313
11110355966421
125057420a129
1323562c98613
141115ab6405b
1581b0e32be3
hex48a4a65c31

312000011313 has 8 divisors (see below), whose sum is σ = 437894752800. Its totient is φ = 197052638688.

The previous prime is 312000011287. The next prime is 312000011333. The reversal of 312000011313 is 313110000213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 312000011313 - 225 = 311966456881 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 312000011292 and 312000011301.

It is not an unprimeable number, because it can be changed into a prime (312000011333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2736842148 + ... + 2736842261.

It is an arithmetic number, because the mean of its divisors is an integer number (54736844100).

Almost surely, 2312000011313 is an apocalyptic number.

It is an amenable number.

312000011313 is a deficient number, since it is larger than the sum of its proper divisors (125894741487).

312000011313 is a wasteful number, since it uses less digits than its factorization.

312000011313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5473684431.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 312000011313 its reverse (313110000213), we get a palindrome (625110011526).

It can be divided in two parts, 3120000 and 11313, that added together give a palindrome (3131313).

The spelling of 312000011313 in words is "three hundred twelve billion, eleven thousand, three hundred thirteen".

Divisors: 1 3 19 57 5473684409 16421053227 104000003771 312000011313