312000111201401 has 4 divisors (see below), whose sum is σ = 356571555658752. Its totient is φ = 267428666744052.

The previous prime is 312000111201379. The next prime is 312000111201403. The reversal of 312000111201401 is 104102111000213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 312000111201401 - 2²² = 312000107007097 is a prime.

It is a super-3 number, since 3×312000111201401³ (a number of 44 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 312000111201401.

It is not an unprimeable number, because it can be changed into a prime (312000111201403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22285722228665 + ... + 22285722228678.

It is an arithmetic number, because the mean of its divisors is an integer number (89142888914688).

Almost surely, 2^{312000111201401} is an apocalyptic number.

It is an amenable number.

312000111201401 is a deficient number, since it is larger than the sum of its proper divisors (44571444457351).

312000111201401 is an equidigital number, since it uses as much as digits as its factorization.

312000111201401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44571444457350.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 312000111201401 its reverse (104102111000213), we get a palindrome (416102222201614).

The spelling of 312000111201401 in words is "three hundred twelve trillion, one hundred eleven million, two hundred one thousand, four hundred one".