Base | Representation |
---|---|
bin | 100011011110001000011011… |
… | …0000100111000100011110011 |
3 | 1111220201100011212012122220211 |
4 | 1012330100312010320203303 |
5 | 311343340214421004111 |
6 | 3023324521023244551 |
7 | 122501403436562263 |
oct | 10674206604704363 |
9 | 1456640155178824 |
10 | 312004511500531 |
11 | 9046140888a463 |
12 | 2abb0693749757 |
13 | 10512b8c696a35 |
14 | 57091556757a3 |
15 | 2610e47890521 |
hex | 11bc4361388f3 |
312004511500531 has 4 divisors (see below), whose sum is σ = 322763287759200. Its totient is φ = 301245735241864.
The previous prime is 312004511500421. The next prime is 312004511500537. The reversal of 312004511500531 is 135005115400213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 312004511500531 - 211 = 312004511498483 is a prime.
It is a super-2 number, since 2×3120045115005312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 312004511500493 and 312004511500502.
It is not an unprimeable number, because it can be changed into a prime (312004511500537) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5379388129291 + ... + 5379388129348.
It is an arithmetic number, because the mean of its divisors is an integer number (80690821939800).
Almost surely, 2312004511500531 is an apocalyptic number.
312004511500531 is a deficient number, since it is larger than the sum of its proper divisors (10758776258669).
312004511500531 is a wasteful number, since it uses less digits than its factorization.
312004511500531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10758776258668.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 312004511500531 its reverse (135005115400213), we get a palindrome (447009626900744).
The spelling of 312004511500531 in words is "three hundred twelve trillion, four billion, five hundred eleven million, five hundred thousand, five hundred thirty-one".
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