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3120112112003 = 3179842624959
BaseRepresentation
bin101101011001110101001…
…011001001000110000011
3102001021112222101202200222
4231121311023021012003
5402104442200041003
610345205410533255
7441264200235455
oct55316513110603
912037488352628
103120112112003
11aa3260a45247
1242484729722b
131982c100ba23
14ab02b0a42d5
1556264492c38
hex2d6752c9183

3120112112003 has 4 divisors (see below), whose sum is σ = 3129954737280. Its totient is φ = 3110269486728.

The previous prime is 3120112111957. The next prime is 3120112112011. The reversal of 3120112112003 is 3002112110213.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3120112112003 - 210 = 3120112110979 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3120117112003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4921312163 + ... + 4921312796.

It is an arithmetic number, because the mean of its divisors is an integer number (782488684320).

Almost surely, 23120112112003 is an apocalyptic number.

3120112112003 is a deficient number, since it is larger than the sum of its proper divisors (9842625277).

3120112112003 is an equidigital number, since it uses as much as digits as its factorization.

3120112112003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9842625276.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 3120112112003 its reverse (3002112110213), we get a palindrome (6122224222216).

The spelling of 3120112112003 in words is "three trillion, one hundred twenty billion, one hundred twelve million, one hundred twelve thousand, three".

Divisors: 1 317 9842624959 3120112112003