312014113 has 4 divisors (see below), whose sum is σ = 325579968. Its totient is φ = 298448260.

The previous prime is 312014093. The next prime is 312014117. The reversal of 312014113 is 311410213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311410213 = 811 ⋅383983.

It is a cyclic number.

It is not a de Polignac number, because 312014113 - 2⁹ = 312013601 is a prime.

It is a super-2 number, since 2×312014113² = 194705613422353538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312014117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6782893 + ... + 6782938.

It is an arithmetic number, because the mean of its divisors is an integer number (81394992).

Almost surely, 2^312014113 is an apocalyptic number.

It is an amenable number.

312014113 is a deficient number, since it is larger than the sum of its proper divisors (13565855).

312014113 is a wasteful number, since it uses less digits than its factorization.

312014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13565854.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 312014113 is about 17663.9212237827. The cubic root of 312014113 is about 678.2525149801.

Adding to 312014113 its reverse (311410213), we get a palindrome (623424326).

The spelling of 312014113 in words is "three hundred twelve million, fourteen thousand, one hundred thirteen".