Base | Representation |
---|---|
bin | 1110001100001000001000… |
… | …10101110001100000100001 |
3 | 11002110222102102122222220110 |
4 | 13012010010111301200201 |
5 | 13042212231104101423 |
6 | 150210244235201533 |
7 | 6400225452511062 |
oct | 706040425614041 |
9 | 132428372588813 |
10 | 31203010222113 |
11 | 9a4013889a614 |
12 | 35bb428ba62a9 |
13 | 145457b57a172 |
14 | 79c33b5bc569 |
15 | 3919dddc7193 |
hex | 1c6104571821 |
31203010222113 has 16 divisors (see below), whose sum is σ = 41620508246016. Its totient is φ = 20793760883280.
The previous prime is 31203010222099. The next prime is 31203010222121. The reversal of 31203010222113 is 31122201030213.
It is not a de Polignac number, because 31203010222113 - 218 = 31203009959969 is a prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 31203010222113.
It is not an unprimeable number, because it can be changed into a prime (31203010222913) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 93855568 + ... + 94187438.
It is an arithmetic number, because the mean of its divisors is an integer number (2601281765376).
Almost surely, 231203010222113 is an apocalyptic number.
It is an amenable number.
31203010222113 is a deficient number, since it is larger than the sum of its proper divisors (10417498023903).
31203010222113 is a wasteful number, since it uses less digits than its factorization.
31203010222113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 344204.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 31203010222113 its reverse (31122201030213), we get a palindrome (62325211252326).
The spelling of 31203010222113 in words is "thirty-one trillion, two hundred three billion, ten million, two hundred twenty-two thousand, one hundred thirteen".
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