Base | Representation |
---|---|
bin | 101101011010001000110… |
… | …011010001101110010011 |
3 | 102001022101221000100012112 |
4 | 231122020303101232103 |
5 | 402111130444301321 |
6 | 10345302212415535 |
7 | 441305306160422 |
oct | 55321063215623 |
9 | 12038357010175 |
10 | 3120441400211 |
11 | aa340a903363 |
12 | 4249196175ab |
13 | 1983442c2815 |
14 | ab05cadd2b9 |
15 | 56283339a5b |
hex | 2d688cd1b93 |
3120441400211 has 4 divisors (see below), whose sum is σ = 3303996776712. Its totient is φ = 2936886023712.
The previous prime is 3120441400151. The next prime is 3120441400213. The reversal of 3120441400211 is 1120041440213.
3120441400211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3120441400211 - 226 = 3120374291347 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3120441400213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91777688225 + ... + 91777688258.
It is an arithmetic number, because the mean of its divisors is an integer number (825999194178).
Almost surely, 23120441400211 is an apocalyptic number.
3120441400211 is a deficient number, since it is larger than the sum of its proper divisors (183555376501).
3120441400211 is a wasteful number, since it uses less digits than its factorization.
3120441400211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 183555376500.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 3120441400211 its reverse (1120041440213), we get a palindrome (4240482840424).
The spelling of 3120441400211 in words is "three trillion, one hundred twenty billion, four hundred forty-one million, four hundred thousand, two hundred eleven".
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