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3120443042545 = 56199100675691
BaseRepresentation
bin101101011010001000111…
…001100010101011110001
3102001022102001002210001201
4231122020321202223301
5402111131404330140
610345302311531201
7441305326140523
oct55321071425361
912038361083051
103120443042545
11aa3410825264
1242491a089b01
1319834474920a
14ab05d009a13
155628356149a
hex2d688e62af1

3120443042545 has 8 divisors (see below), whose sum is σ = 3745135742400. Its totient is φ = 2495951706480.

The previous prime is 3120443042533. The next prime is 3120443042579. The reversal of 3120443042545 is 5452403440213.

3120443042545 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 3120443042545 - 27 = 3120443042417 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50306851 + ... + 50368840.

It is an arithmetic number, because the mean of its divisors is an integer number (468141967800).

Almost surely, 23120443042545 is an apocalyptic number.

It is an amenable number.

3120443042545 is a deficient number, since it is larger than the sum of its proper divisors (624692699855).

3120443042545 is a wasteful number, since it uses less digits than its factorization.

3120443042545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100681895.

The product of its (nonzero) digits is 230400, while the sum is 37.

Adding to 3120443042545 its reverse (5452403440213), we get a palindrome (8572846482758).

The spelling of 3120443042545 in words is "three trillion, one hundred twenty billion, four hundred forty-three million, forty-two thousand, five hundred forty-five".

Divisors: 1 5 6199 30995 100675691 503378455 624088608509 3120443042545