Base | Representation |
---|---|
bin | 1110001100010101001011… |
… | …10000001000101111110001 |
3 | 11002111122111111001202122012 |
4 | 13012022211300020233301 |
5 | 13042321101341411423 |
6 | 150213403202052305 |
7 | 6400564136224622 |
oct | 706124560105761 |
9 | 132448444052565 |
10 | 31210013232113 |
11 | 9a4310190a691 |
12 | 360086234a095 |
13 | 1455126398171 |
14 | 79c8036bda49 |
15 | 391c9dad8078 |
hex | 1c62a5c08bf1 |
31210013232113 has 4 divisors (see below), whose sum is σ = 31210120273920. Its totient is φ = 31209906190308.
The previous prime is 31210013232077. The next prime is 31210013232119. The reversal of 31210013232113 is 31123231001213.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 31210013232113 - 218 = 31210012969969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31210013232119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53082353 + ... + 53667086.
It is an arithmetic number, because the mean of its divisors is an integer number (7802530068480).
Almost surely, 231210013232113 is an apocalyptic number.
It is an amenable number.
31210013232113 is a deficient number, since it is larger than the sum of its proper divisors (107041807).
31210013232113 is a wasteful number, since it uses less digits than its factorization.
31210013232113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107041806.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 31210013232113 its reverse (31123231001213), we get a palindrome (62333244233326).
The spelling of 31210013232113 in words is "thirty-one trillion, two hundred ten billion, thirteen million, two hundred thirty-two thousand, one hundred thirteen".
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