3121001440113 has 8 divisors (see below), whose sum is σ = 4161507654976. Its totient is φ = 2080581426000.

The previous prime is 3121001440111. The next prime is 3121001440121. The reversal of 3121001440113 is 3110441001213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 3121001440113 - 2¹ = 3121001440111 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 3121001440113.

It is not an unprimeable number, because it can be changed into a prime (3121001440111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21465658 + ... + 21610563.

It is an arithmetic number, because the mean of its divisors is an integer number (520188456872).

Almost surely, 2^{3121001440113} is an apocalyptic number.

It is an amenable number.

3121001440113 is a deficient number, since it is larger than the sum of its proper divisors (1040506214863).

3121001440113 is a wasteful number, since it uses less digits than its factorization.

3121001440113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43100375.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 3121001440113 its reverse (3110441001213), we get a palindrome (6231442441326).

The spelling of 3121001440113 in words is "three trillion, one hundred twenty-one billion, one million, four hundred forty thousand, one hundred thirteen".