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31210104113 = 226713767139
BaseRepresentation
bin11101000100010001…
…000110010100110001
32222120002022120010222
4131010101012110301
51002404241312423
622200540502425
72153262336116
oct350421062461
988502276128
1031210104113
1112266321181
12607024aa15
132c34cb6636
14172104890d
15c29ead3c8
hex744446531

31210104113 has 4 divisors (see below), whose sum is σ = 31223873520. Its totient is φ = 31196334708.

The previous prime is 31210104071. The next prime is 31210104157. The reversal of 31210104113 is 31140101213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31210104113 - 232 = 26915136817 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31210104091 and 31210104100.

It is not an unprimeable number, because it can be changed into a prime (31212104113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6881303 + ... + 6885836.

It is an arithmetic number, because the mean of its divisors is an integer number (7805968380).

Almost surely, 231210104113 is an apocalyptic number.

It is an amenable number.

31210104113 is a deficient number, since it is larger than the sum of its proper divisors (13769407).

31210104113 is a wasteful number, since it uses less digits than its factorization.

31210104113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13769406.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 31210104113 its reverse (31140101213), we get a palindrome (62350205326).

The spelling of 31210104113 in words is "thirty-one billion, two hundred ten million, one hundred four thousand, one hundred thirteen".

Divisors: 1 2267 13767139 31210104113