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31211131301113 = 58675319776939
BaseRepresentation
bin1110001100010111010000…
…11001001110110011111001
311002111202101101220112222011
413012023220121032303321
513042330344103113423
6150214110142125521
76400633633525201
oct706135031166371
9132452341815864
1031211131301113
119a43625a46455
123600b148808a1
131455273c0435a
1479c8abda3401
15391d16d3cb0d
hex1c62e864ecf9

31211131301113 has 4 divisors (see below), whose sum is σ = 31216451083920. Its totient is φ = 31205811518308.

The previous prime is 31211131301011. The next prime is 31211131301167. The reversal of 31211131301113 is 31110313111213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31211131301113 - 217 = 31211131170041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31211131301813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2659882603 + ... + 2659894336.

It is an arithmetic number, because the mean of its divisors is an integer number (7804112770980).

Almost surely, 231211131301113 is an apocalyptic number.

It is an amenable number.

31211131301113 is a deficient number, since it is larger than the sum of its proper divisors (5319782807).

31211131301113 is an equidigital number, since it uses as much as digits as its factorization.

31211131301113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5319782806.

The product of its (nonzero) digits is 162, while the sum is 22.

Adding to 31211131301113 its reverse (31110313111213), we get a palindrome (62321444412326).

The spelling of 31211131301113 in words is "thirty-one trillion, two hundred eleven billion, one hundred thirty-one million, three hundred one thousand, one hundred thirteen".

Divisors: 1 5867 5319776939 31211131301113