Base | Representation |
---|---|
bin | 11101000100011101… |
… | …000100111001100011 |
3 | 2222120022020002021012 |
4 | 131010131010321203 |
5 | 1002411042302003 |
6 | 22201132051135 |
7 | 2153331124244 |
oct | 350435047143 |
9 | 88508202235 |
10 | 31213244003 |
11 | 12268076227 |
12 | 6071303aab |
13 | 2c35845866 |
14 | 1721624ccb |
15 | c2a3cd8d8 |
hex | 744744e63 |
31213244003 has 4 divisors (see below), whose sum is σ = 31225868088. Its totient is φ = 31200619920.
The previous prime is 31213243979. The next prime is 31213244017. The reversal of 31213244003 is 30044231213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31213244003 - 26 = 31213243939 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 31213244003.
It is not an unprimeable number, because it can be changed into a prime (31213244053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6308333 + ... + 6313278.
It is an arithmetic number, because the mean of its divisors is an integer number (7806467022).
Almost surely, 231213244003 is an apocalyptic number.
31213244003 is a deficient number, since it is larger than the sum of its proper divisors (12624085).
31213244003 is a wasteful number, since it uses less digits than its factorization.
31213244003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12624084.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 31213244003 its reverse (30044231213), we get a palindrome (61257475216).
The spelling of 31213244003 in words is "thirty-one billion, two hundred thirteen million, two hundred forty-four thousand, three".
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