Base | Representation |
---|---|
bin | 1110001100100111111000… |
… | …00111100000010111101011 |
3 | 11002112121102010000210020022 |
4 | 13012103330013200113223 |
5 | 13043002131321231410 |
6 | 150222143254351055 |
7 | 6401400665410361 |
oct | 706237407402753 |
9 | 132477363023208 |
10 | 31220052133355 |
11 | 9a47393584788 |
12 | 36027a435b48b |
13 | 1456066156007 |
14 | 79d0b6a8b631 |
15 | 39218a0cc455 |
hex | 1c64fc1e05eb |
31220052133355 has 4 divisors (see below), whose sum is σ = 37464062560032. Its totient is φ = 24976041706680.
The previous prime is 31220052133349. The next prime is 31220052133357. The reversal of 31220052133355 is 55333125002213.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 31220052133355 - 228 = 31219783697899 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31220052133357) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3122005213331 + ... + 3122005213340.
It is an arithmetic number, because the mean of its divisors is an integer number (9366015640008).
Almost surely, 231220052133355 is an apocalyptic number.
31220052133355 is a deficient number, since it is larger than the sum of its proper divisors (6244010426677).
31220052133355 is an equidigital number, since it uses as much as digits as its factorization.
31220052133355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6244010426676.
The product of its (nonzero) digits is 81000, while the sum is 35.
Adding to 31220052133355 its reverse (55333125002213), we get a palindrome (86553177135568).
The spelling of 31220052133355 in words is "thirty-one trillion, two hundred twenty billion, fifty-two million, one hundred thirty-three thousand, three hundred fifty-five".
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