Base | Representation |
---|---|
bin | 101101011011101100010… |
… | …001101111010010111001 |
3 | 102001110201020101202112110 |
4 | 231123230101233102321 |
5 | 402123040221030131 |
6 | 10350135551402533 |
7 | 441364542636153 |
oct | 55335421572271 |
9 | 12043636352473 |
10 | 3122110330041 |
11 | aa409698500a |
12 | 425104523449 |
13 | 19854bcb0c71 |
14 | ab17a617ad3 |
15 | 5632eb02646 |
hex | 2d6ec46f4b9 |
3122110330041 has 4 divisors (see below), whose sum is σ = 4162813773392. Its totient is φ = 2081406886692.
The previous prime is 3122110329929. The next prime is 3122110330051. The reversal of 3122110330041 is 1400330112213.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 3122110330041 - 213 = 3122110321849 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3122110330051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 520351721671 + ... + 520351721676.
It is an arithmetic number, because the mean of its divisors is an integer number (1040703443348).
Almost surely, 23122110330041 is an apocalyptic number.
It is an amenable number.
3122110330041 is a deficient number, since it is larger than the sum of its proper divisors (1040703443351).
3122110330041 is a wasteful number, since it uses less digits than its factorization.
3122110330041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1040703443350.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 3122110330041 its reverse (1400330112213), we get a palindrome (4522440442254).
The spelling of 3122110330041 in words is "three trillion, one hundred twenty-two billion, one hundred ten million, three hundred thirty thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •