Base | Representation |
---|---|
bin | 100011011111110111001101… |
… | …0001000000000101111010001 |
3 | 1111221120002020122022101011121 |
4 | 1012333232122020000233101 |
5 | 311411234430242241340 |
6 | 3024030103455242241 |
7 | 122524525036202224 |
oct | 10677563210005721 |
9 | 1457502218271147 |
10 | 312242413243345 |
11 | 9054329a150a52 |
12 | 2b02a808519381 |
13 | 1052c44413a960 |
14 | 57168833ad5bb |
15 | 261721d4ca94a |
hex | 11bfb9a200bd1 |
312242413243345 has 16 divisors (see below), whose sum is σ = 403513816934592. Its totient is φ = 230578701750720.
The previous prime is 312242413243309. The next prime is 312242413243421. The reversal of 312242413243345 is 543342314242213.
It is not a de Polignac number, because 312242413243345 - 213 = 312242413235153 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52668214 + ... + 58296016.
It is an arithmetic number, because the mean of its divisors is an integer number (25219613558412).
Almost surely, 2312242413243345 is an apocalyptic number.
It is an amenable number.
312242413243345 is a deficient number, since it is larger than the sum of its proper divisors (91271403691247).
312242413243345 is a wasteful number, since it uses less digits than its factorization.
312242413243345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6481392.
The product of its digits is 1658880, while the sum is 43.
Adding to 312242413243345 its reverse (543342314242213), we get a palindrome (855584727485558).
The spelling of 312242413243345 in words is "three hundred twelve trillion, two hundred forty-two billion, four hundred thirteen million, two hundred forty-three thousand, three hundred forty-five".
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