Base | Representation |
---|---|
bin | 1110001100110010000110… |
… | …01110000111010001100001 |
3 | 11002120010120120110001212111 |
4 | 13012121003032013101201 |
5 | 13043044401220441301 |
6 | 150224452014555321 |
7 | 6401653663551040 |
oct | 706310316072141 |
9 | 132503516401774 |
10 | 31225540015201 |
11 | 9a4974a321624 |
12 | 3603876208b41 |
13 | 145672c0b5c8c |
14 | 79d47786c557 |
15 | 3923abca6551 |
hex | 1c6643387461 |
31225540015201 has 16 divisors (see below), whose sum is σ = 35694363369600. Its totient is φ = 26758725343488.
The previous prime is 31225540015199. The next prime is 31225540015207. The reversal of 31225540015201 is 10251004552213.
It is a cyclic number.
It is not a de Polignac number, because 31225540015201 - 21 = 31225540015199 is a prime.
It is a super-3 number, since 3×312255400152013 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31225540015207) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1045261401 + ... + 1045291273.
It is an arithmetic number, because the mean of its divisors is an integer number (2230897710600).
Almost surely, 231225540015201 is an apocalyptic number.
It is an amenable number.
31225540015201 is a deficient number, since it is larger than the sum of its proper divisors (4468823354399).
31225540015201 is a wasteful number, since it uses less digits than its factorization.
31225540015201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58488.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 31225540015201 its reverse (10251004552213), we get a palindrome (41476544567414).
The spelling of 31225540015201 in words is "thirty-one trillion, two hundred twenty-five billion, five hundred forty million, fifteen thousand, two hundred one".
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