Base | Representation |
---|---|
bin | 101101011100101110000… |
… | …000110110101010001011 |
3 | 102001120120002122100201101 |
4 | 231130232000312222023 |
5 | 402132320034400021 |
6 | 10350441230002231 |
7 | 441434064114412 |
oct | 55345600665213 |
9 | 12046502570641 |
10 | 3123213200011 |
11 | aa460247a5a3 |
12 | 425371946377 |
13 | 198696628048 |
14 | ab242ca2479 |
15 | 56396853a91 |
hex | 2d72e036a8b |
3123213200011 has 4 divisors (see below), whose sum is σ = 3124115084272. Its totient is φ = 3122311315752.
The previous prime is 3123213199933. The next prime is 3123213200077. The reversal of 3123213200011 is 1100023123213.
3123213200011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3123213200011 - 211 = 3123213197963 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3123213200711) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 450936936 + ... + 450943861.
It is an arithmetic number, because the mean of its divisors is an integer number (781028771068).
Almost surely, 23123213200011 is an apocalyptic number.
3123213200011 is a deficient number, since it is larger than the sum of its proper divisors (901884261).
3123213200011 is an equidigital number, since it uses as much as digits as its factorization.
3123213200011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 901884260.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 3123213200011 its reverse (1100023123213), we get a palindrome (4223236323224).
The spelling of 3123213200011 in words is "three trillion, one hundred twenty-three billion, two hundred thirteen million, two hundred thousand, eleven".
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