312340433 has 4 divisors (see below), whose sum is σ = 319604208. Its totient is φ = 305076660.

The previous prime is 312340397. The next prime is 312340447. The reversal of 312340433 is 334043213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334043213 = 7 ⋅47720459.

It is a cyclic number.

It is not a de Polignac number, because 312340433 - 2¹⁰ = 312339409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 312340399 and 312340408.

It is not an unprimeable number, because it can be changed into a prime (312340493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3631823 + ... + 3631908.

It is an arithmetic number, because the mean of its divisors is an integer number (79901052).

Almost surely, 2^312340433 is an apocalyptic number.

It is an amenable number.

312340433 is a deficient number, since it is larger than the sum of its proper divisors (7263775).

312340433 is an equidigital number, since it uses as much as digits as its factorization.

312340433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7263774.

The product of its (nonzero) digits is 2592, while the sum is 23.

The square root of 312340433 is about 17673.1557170755. The cubic root of 312340433 is about 678.4888827573.

Adding to 312340433 its reverse (334043213), we get a palindrome (646383646).

The spelling of 312340433 in words is "three hundred twelve million, three hundred forty thousand, four hundred thirty-three".