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3123920948403 = 37831713296053
BaseRepresentation
bin101101011101011000001…
…100101100110010110011
3102001122101102101200222210
4231131120030230302303
5402140242230322103
610351035351303203
7441460446636663
oct55353014546263
912048342350883
103123920948403
11aa4935a31422
1242552a97ab03
1319877a14b188
14ab2acc961a3
15563d8a56e03
hex2d75832ccb3

3123920948403 has 8 divisors (see below), whose sum is σ = 4165281428688. Its totient is φ = 2082587216864.

The previous prime is 3123920948389. The next prime is 3123920948419. The reversal of 3123920948403 is 3048490293213.

3123920948403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3123920948403 - 234 = 3106741079219 is a prime.

It is a super-3 number, since 3×31239209484033 (a number of 38 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (3123920948303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6413076 + ... + 6882977.

It is an arithmetic number, because the mean of its divisors is an integer number (520660178586).

Almost surely, 23123920948403 is an apocalyptic number.

3123920948403 is a deficient number, since it is larger than the sum of its proper divisors (1041360480285).

3123920948403 is a wasteful number, since it uses less digits than its factorization.

3123920948403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13374373.

The product of its (nonzero) digits is 1119744, while the sum is 48.

The spelling of 3123920948403 in words is "three trillion, one hundred twenty-three billion, nine hundred twenty million, nine hundred forty-eight thousand, four hundred three".

Divisors: 1 3 78317 234951 13296053 39888159 1041306982801 3123920948403