Base | Representation |
---|---|
bin | 101101011101100011001… |
… | …000100001001000100011 |
3 | 102001122212012121002020211 |
4 | 231131203020201020203 |
5 | 402141131211321233 |
6 | 10351105503314551 |
7 | 441465135156334 |
oct | 55354310411043 |
9 | 12048765532224 |
10 | 3124104401443 |
11 | aa4a1a542403 |
12 | 4255802aba57 |
13 | 1987a916097c |
14 | ab2c93ac28b |
15 | 563e9be35cd |
hex | 2d763221223 |
3124104401443 has 4 divisors (see below), whose sum is σ = 3125007064368. Its totient is φ = 3123201738520.
The previous prime is 3124104401437. The next prime is 3124104401459. The reversal of 3124104401443 is 3441044014213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3124104401443 - 225 = 3124070847011 is a prime.
It is a super-2 number, since 2×31241044014432 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3124104401413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 451326271 + ... + 451333192.
It is an arithmetic number, because the mean of its divisors is an integer number (781251766092).
Almost surely, 23124104401443 is an apocalyptic number.
3124104401443 is a deficient number, since it is larger than the sum of its proper divisors (902662925).
3124104401443 is an equidigital number, since it uses as much as digits as its factorization.
3124104401443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 902662924.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 3124104401443 its reverse (3441044014213), we get a palindrome (6565148415656).
The spelling of 3124104401443 in words is "three trillion, one hundred twenty-four billion, one hundred four million, four hundred one thousand, four hundred forty-three".
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