Base | Representation |
---|---|
bin | 1001000101111100110… |
… | …11000111001010000011 |
3 | 1002212102221201120200210 |
4 | 10202332123013022003 |
5 | 20104330200023210 |
6 | 355310211045203 |
7 | 31400236532220 |
oct | 4427633071203 |
9 | 1085387646623 |
10 | 312432423555 |
11 | 110557a5a10a |
12 | 50674ba0803 |
13 | 23601747b55 |
14 | 1119c364947 |
15 | 81d8d99e20 |
hex | 48be6c7283 |
312432423555 has 16 divisors (see below), whose sum is σ = 571305003264. Its totient is φ = 142826250720.
The previous prime is 312432423539. The next prime is 312432423599. The reversal of 312432423555 is 555324234213.
It is not a de Polignac number, because 312432423555 - 24 = 312432423539 is a prime.
It is a super-2 number, since 2×3124324235552 (a number of 24 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1487773341 + ... + 1487773550.
It is an arithmetic number, because the mean of its divisors is an integer number (35706562704).
Almost surely, 2312432423555 is an apocalyptic number.
312432423555 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
312432423555 is a deficient number, since it is larger than the sum of its proper divisors (258872579709).
312432423555 is a wasteful number, since it uses less digits than its factorization.
312432423555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2975546906.
The product of its digits is 432000, while the sum is 39.
Adding to 312432423555 its reverse (555324234213), we get a palindrome (867756657768).
The spelling of 312432423555 in words is "three hundred twelve billion, four hundred thirty-two million, four hundred twenty-three thousand, five hundred fifty-five".
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