Base | Representation |
---|---|
bin | 1110001101010011011011… |
… | …00111010101110000110011 |
3 | 11002121211202102202101202020 |
4 | 13012221231213111300303 |
5 | 13043343021332443103 |
6 | 150241011211522523 |
7 | 6403156230605646 |
oct | 706515547256063 |
9 | 132554672671666 |
10 | 31243431140403 |
11 | 9a562a0400809 |
12 | 3607229a59443 |
13 | 14583208b63b1 |
14 | 7a0293a37a5d |
15 | 392aa7805753 |
hex | 1c6a6d9d5c33 |
31243431140403 has 4 divisors (see below), whose sum is σ = 41657908187208. Its totient is φ = 20828954093600.
The previous prime is 31243431140401. The next prime is 31243431140431. The reversal of 31243431140403 is 30404113434213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31243431140403 - 21 = 31243431140401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31243431140401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5207238523398 + ... + 5207238523403.
It is an arithmetic number, because the mean of its divisors is an integer number (10414477046802).
Almost surely, 231243431140403 is an apocalyptic number.
31243431140403 is a deficient number, since it is larger than the sum of its proper divisors (10414477046805).
31243431140403 is a wasteful number, since it uses less digits than its factorization.
31243431140403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10414477046804.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 31243431140403 its reverse (30404113434213), we get a palindrome (61647544574616).
The spelling of 31243431140403 in words is "thirty-one trillion, two hundred forty-three billion, four hundred thirty-one million, one hundred forty thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •