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31243431140403 = 310414477046801
BaseRepresentation
bin1110001101010011011011…
…00111010101110000110011
311002121211202102202101202020
413012221231213111300303
513043343021332443103
6150241011211522523
76403156230605646
oct706515547256063
9132554672671666
1031243431140403
119a562a0400809
123607229a59443
1314583208b63b1
147a0293a37a5d
15392aa7805753
hex1c6a6d9d5c33

31243431140403 has 4 divisors (see below), whose sum is σ = 41657908187208. Its totient is φ = 20828954093600.

The previous prime is 31243431140401. The next prime is 31243431140431. The reversal of 31243431140403 is 30404113434213.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31243431140403 - 21 = 31243431140401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (31243431140401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5207238523398 + ... + 5207238523403.

It is an arithmetic number, because the mean of its divisors is an integer number (10414477046802).

Almost surely, 231243431140403 is an apocalyptic number.

31243431140403 is a deficient number, since it is larger than the sum of its proper divisors (10414477046805).

31243431140403 is a wasteful number, since it uses less digits than its factorization.

31243431140403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10414477046804.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 31243431140403 its reverse (30404113434213), we get a palindrome (61647544574616).

The spelling of 31243431140403 in words is "thirty-one trillion, two hundred forty-three billion, four hundred thirty-one million, one hundred forty thousand, four hundred three".

Divisors: 1 3 10414477046801 31243431140403