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3125143902889 = 31191001969831
BaseRepresentation
bin101101011110100001000…
…101111001101010101001
3102001202112122121020011101
4231132201011321222221
5402200243314343024
610351400555401401
7441532656610651
oct55364105715251
912052478536141
103125143902889
11aa5403296208
12425810453261
1319891361b798
14ab38747d361
155645b0c8c44
hex2d7a1179aa9

3125143902889 has 4 divisors (see below), whose sum is σ = 3126145875840. Its totient is φ = 3124141929940.

The previous prime is 3125143902863. The next prime is 3125143902961. The reversal of 3125143902889 is 9882093415213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3125143902889 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3125143906889) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500981797 + ... + 500988034.

It is an arithmetic number, because the mean of its divisors is an integer number (781536468960).

Almost surely, 23125143902889 is an apocalyptic number.

It is an amenable number.

3125143902889 is a deficient number, since it is larger than the sum of its proper divisors (1001972951).

3125143902889 is a wasteful number, since it uses less digits than its factorization.

3125143902889 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1001972950.

The product of its (nonzero) digits is 3732480, while the sum is 55.

The spelling of 3125143902889 in words is "three trillion, one hundred twenty-five billion, one hundred forty-three million, nine hundred two thousand, eight hundred eighty-nine".

Divisors: 1 3119 1001969831 3125143902889