3125344531 has 4 divisors (see below), whose sum is σ = 3127160152. Its totient is φ = 3123528912.

The previous prime is 3125344513. The next prime is 3125344543. The reversal of 3125344531 is 1354435213.

3125344531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1354435213 = 8783 ⋅154211.

It is a cyclic number.

It is not a de Polignac number, because 3125344531 - 2¹¹ = 3125342483 is a prime.

It is a super-2 number, since 2×3125344531² = 19535556874903219922, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3125344493 and 3125344502.

It is not an unprimeable number, because it can be changed into a prime (3125344591) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 905226 + ... + 908671.

It is an arithmetic number, because the mean of its divisors is an integer number (781790038).

Almost surely, 2^3125344531 is an apocalyptic number.

3125344531 is a deficient number, since it is larger than the sum of its proper divisors (1815621).

3125344531 is a wasteful number, since it uses less digits than its factorization.

3125344531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1815620.

The product of its digits is 21600, while the sum is 31.

The square root of 3125344531 is about 55904.7809315089. The cubic root of 3125344531 is about 1462.0625959190.

Adding to 3125344531 its reverse (1354435213), we get a palindrome (4479779744).

The spelling of 3125344531 in words is "three billion, one hundred twenty-five million, three hundred forty-four thousand, five hundred thirty-one".