Base | Representation |
---|---|
bin | 1110001101101001101110… |
… | …10001011011110111010011 |
3 | 11002122222122212102110202111 |
4 | 13012310313101123313103 |
5 | 13044042032002033301 |
6 | 150250311242530151 |
7 | 6404062025211400 |
oct | 706646721336723 |
9 | 132588585373674 |
10 | 31255404330451 |
11 | 9a60384a106a4 |
12 | 360960b806957 |
13 | 14594ab321c32 |
14 | 7a0aabc772a7 |
15 | 393058a2c551 |
hex | 1c6d3745bdd3 |
31255404330451 has 12 divisors (see below), whose sum is σ = 37612062918720. Its totient is φ = 25866541513680.
The previous prime is 31255404330433. The next prime is 31255404330473. The reversal of 31255404330451 is 15403340455213.
It is a de Polignac number, because none of the positive numbers 2k-31255404330451 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31255404330151) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10997677795 + ... + 10997680636.
It is an arithmetic number, because the mean of its divisors is an integer number (3134338576560).
Almost surely, 231255404330451 is an apocalyptic number.
31255404330451 is a deficient number, since it is larger than the sum of its proper divisors (6356658588269).
31255404330451 is a wasteful number, since it uses less digits than its factorization.
31255404330451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21995358474 (or 21995358467 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 31255404330451 its reverse (15403340455213), we get a palindrome (46658744785664).
The spelling of 31255404330451 in words is "thirty-one trillion, two hundred fifty-five billion, four hundred four million, three hundred thirty thousand, four hundred fifty-one".
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