Base | Representation |
---|---|
bin | 11101001001101000… |
… | …011111011000000001 |
3 | 2222210100200221121222 |
4 | 131021220133120001 |
5 | 1003100312401423 |
6 | 22213514124425 |
7 | 2155434435221 |
oct | 351150373001 |
9 | 88710627558 |
10 | 31300122113 |
11 | 12302115017 |
12 | 6096420715 |
13 | 2c4a843820 |
14 | 172cd9c081 |
15 | c32d403c8 |
hex | 749a1f601 |
31300122113 has 8 divisors (see below), whose sum is σ = 33722711400. Its totient is φ = 28879659648.
The previous prime is 31300122109. The next prime is 31300122157. The reversal of 31300122113 is 31122100313.
It can be written as a sum of positive squares in 4 ways, for example, as 1541112049 + 29759010064 = 39257^2 + 172508^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31300122113 - 22 = 31300122109 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31300122091 and 31300122100.
It is not an unprimeable number, because it can be changed into a prime (31300122013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 501068 + ... + 560061.
It is an arithmetic number, because the mean of its divisors is an integer number (4215338925).
Almost surely, 231300122113 is an apocalyptic number.
It is an amenable number.
31300122113 is a deficient number, since it is larger than the sum of its proper divisors (2422589287).
31300122113 is a wasteful number, since it uses less digits than its factorization.
31300122113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1063411.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 31300122113 its reverse (31122100313), we get a palindrome (62422222426).
The spelling of 31300122113 in words is "thirty-one billion, three hundred million, one hundred twenty-two thousand, one hundred thirteen".
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