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313001350041 = 31028910140323
BaseRepresentation
bin1001000111000000101…
…01011001001110011001
31002220220121021001010010
410203200111121032121
520112011321200131
6355442453112133
731420315402062
oct4434025311631
91086817231103
10313001350041
1111081a113a96
12507b3628649
1323692583c43
1411213b3d569
15821dccab46
hex48e0559399

313001350041 has 8 divisors (see below), whose sum is σ = 417375735840. Its totient is φ = 208647265472.

The previous prime is 313001350007. The next prime is 313001350099. The reversal of 313001350041 is 140053100313.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-313001350041 is a prime.

It is a super-2 number, since 2×3130013500412 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (313001350001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5039295 + ... + 5101028.

It is an arithmetic number, because the mean of its divisors is an integer number (52171966980).

Almost surely, 2313001350041 is an apocalyptic number.

It is an amenable number.

313001350041 is a deficient number, since it is larger than the sum of its proper divisors (104374385799).

313001350041 is a wasteful number, since it uses less digits than its factorization.

313001350041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10150615.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 313001350041 its reverse (140053100313), we get a palindrome (453054450354).

The spelling of 313001350041 in words is "three hundred thirteen billion, one million, three hundred fifty thousand, forty-one".

Divisors: 1 3 10289 30867 10140323 30420969 104333783347 313001350041