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3130102051 = 25391232809
BaseRepresentation
bin1011101010010001…
…1001000100100011
322002010211122210121
42322210121010203
522402301231201
61234332541111
7140365266646
oct27244310443
98063748717
103130102051
111366951aaa
12734321797
133ab6375bb
142199d1a5d
15134be29a1
hexba919123

3130102051 has 4 divisors (see below), whose sum is σ = 3131337400. Its totient is φ = 3128866704.

The previous prime is 3130102007. The next prime is 3130102057. The reversal of 3130102051 is 1502010313.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1502010313 = 2296558997.

It is a cyclic number.

It is not a de Polignac number, because 3130102051 - 217 = 3129970979 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3130102057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 613866 + ... + 618943.

It is an arithmetic number, because the mean of its divisors is an integer number (782834350).

Almost surely, 23130102051 is an apocalyptic number.

3130102051 is a deficient number, since it is larger than the sum of its proper divisors (1235349).

3130102051 is a wasteful number, since it uses less digits than its factorization.

3130102051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1235348.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 3130102051 is about 55947.3149579138. The cubic root of 3130102051 is about 1462.8040891630.

Adding to 3130102051 its reverse (1502010313), we get a palindrome (4632112364).

The spelling of 3130102051 in words is "three billion, one hundred thirty million, one hundred two thousand, fifty-one".

Divisors: 1 2539 1232809 3130102051