Search a number
-
+
313012113001 = 744716016143
BaseRepresentation
bin1001000111000001111…
…10011100111001101001
31002220221100111212010021
410203200332130321221
520112022100104001
6355443515520441
731420506030010
oct4434076347151
91086840455107
10313012113001
111108251a53a5
12507b7159121
1323694881b63
1411215341a77
15821ec04ba1
hex48e0f9ce69

313012113001 has 4 divisors (see below), whose sum is σ = 357728129152. Its totient is φ = 268296096852.

The previous prime is 313012112999. The next prime is 313012113019. The reversal of 313012113001 is 100311210313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100311210313 = 517119398803.

It is not a de Polignac number, because 313012113001 - 21 = 313012112999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (313012113101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22358008065 + ... + 22358008078.

It is an arithmetic number, because the mean of its divisors is an integer number (89432032288).

Almost surely, 2313012113001 is an apocalyptic number.

It is an amenable number.

313012113001 is a deficient number, since it is larger than the sum of its proper divisors (44716016151).

313012113001 is an equidigital number, since it uses as much as digits as its factorization.

313012113001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44716016150.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 313012113001 its reverse (100311210313), we get a palindrome (413323323314).

The spelling of 313012113001 in words is "three hundred thirteen billion, twelve million, one hundred thirteen thousand, one".

Divisors: 1 7 44716016143 313012113001