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3130125113 = 19164743427
BaseRepresentation
bin1011101010010001…
…1110101100111001
322002010212211102202
42322210132230321
522402303000423
61234333235545
7140365424123
oct27244365471
98063784382
103130125113
111366968365
12734332bb5
133ab644c4b
142199da213
15134be9728
hexba91eb39

3130125113 has 4 divisors (see below), whose sum is σ = 3294868560. Its totient is φ = 2965381668.

The previous prime is 3130125109. The next prime is 3130125127. The reversal of 3130125113 is 3115210313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3130125113 - 22 = 3130125109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3130125143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82371695 + ... + 82371732.

It is an arithmetic number, because the mean of its divisors is an integer number (823717140).

Almost surely, 23130125113 is an apocalyptic number.

It is an amenable number.

3130125113 is a deficient number, since it is larger than the sum of its proper divisors (164743447).

3130125113 is a wasteful number, since it uses less digits than its factorization.

3130125113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164743446.

The product of its (nonzero) digits is 270, while the sum is 20.

The square root of 3130125113 is about 55947.5210621525. The cubic root of 3130125113 is about 1462.8076817088.

Adding to 3130125113 its reverse (3115210313), we get a palindrome (6245335426).

The spelling of 3130125113 in words is "three billion, one hundred thirty million, one hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 19 164743427 3130125113