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31305130401 = 310435043467
BaseRepresentation
bin11101001001111011…
…100110000110100001
32222210201010101201010
4131021323212012201
51003103103133101
622214213331133
72155525134516
oct351173460641
988721111633
1031305130401
1112304a258a6
126098036aa9
132c4b8a82cc
14172d90330d
15c334ce2d6
hex749ee61a1

31305130401 has 4 divisors (see below), whose sum is σ = 41740173872. Its totient is φ = 20870086932.

The previous prime is 31305130397. The next prime is 31305130411. The reversal of 31305130401 is 10403150313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 31305130401 - 22 = 31305130397 is a prime.

It is a super-2 number, since 2×313051304012 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (31305130411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5217521731 + ... + 5217521736.

It is an arithmetic number, because the mean of its divisors is an integer number (10435043468).

Almost surely, 231305130401 is an apocalyptic number.

It is an amenable number.

31305130401 is a deficient number, since it is larger than the sum of its proper divisors (10435043471).

31305130401 is a wasteful number, since it uses less digits than its factorization.

31305130401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10435043470.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 31305130401 its reverse (10403150313), we get a palindrome (41708280714).

The spelling of 31305130401 in words is "thirty-one billion, three hundred five million, one hundred thirty thousand, four hundred one".

Divisors: 1 3 10435043467 31305130401