Base | Representation |
---|---|
bin | 1110001111001111110111… |
… | …10011001111101100101011 |
3 | 11002212020012112112210102111 |
4 | 13013213323303033230223 |
5 | 13100441333212313103 |
6 | 150331420505543151 |
7 | 6411042651314326 |
oct | 707477363175453 |
9 | 132766175483374 |
10 | 31310241135403 |
11 | 9a8166495690a |
12 | 36181744a4ab7 |
13 | 146170a181709 |
14 | 7a35d0b077bd |
15 | 3946b7d3e86d |
hex | 1c79fbccfb2b |
31310241135403 has 4 divisors (see below), whose sum is σ = 31448171713320. Its totient is φ = 31172310557488.
The previous prime is 31310241135377. The next prime is 31310241135431. The reversal of 31310241135403 is 30453114201313.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31310241135403 - 29 = 31310241134891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31310241135443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68965288618 + ... + 68965289071.
It is an arithmetic number, because the mean of its divisors is an integer number (7862042928330).
Almost surely, 231310241135403 is an apocalyptic number.
31310241135403 is a deficient number, since it is larger than the sum of its proper divisors (137930577917).
31310241135403 is a wasteful number, since it uses less digits than its factorization.
31310241135403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137930577916.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 31310241135403 its reverse (30453114201313), we get a palindrome (61763355336716).
The spelling of 31310241135403 in words is "thirty-one trillion, three hundred ten billion, two hundred forty-one million, one hundred thirty-five thousand, four hundred three".
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