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31310245205113 = 74472892172159
BaseRepresentation
bin1110001111001111111000…
…00010110001010001111001
311002212020012211012120000111
413013213330002301101321
513100441340233030423
6150331421133104321
76411043031024350
oct707477402612171
9132766184176014
1031310245205113
119a81667186506
1236181759280a1
13146170ac77c24
147a35d1486997
153946b839560d
hex1c79fc0b1479

31310245205113 has 4 divisors (see below), whose sum is σ = 35783137377280. Its totient is φ = 26837353032948.

The previous prime is 31310245205081. The next prime is 31310245205117. The reversal of 31310245205113 is 31150254201313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31310245205113 - 25 = 31310245205081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31310245205117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2236446086073 + ... + 2236446086086.

It is an arithmetic number, because the mean of its divisors is an integer number (8945784344320).

Almost surely, 231310245205113 is an apocalyptic number.

It is an amenable number.

31310245205113 is a deficient number, since it is larger than the sum of its proper divisors (4472892172167).

31310245205113 is an equidigital number, since it uses as much as digits as its factorization.

31310245205113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4472892172166.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 31310245205113 its reverse (31150254201313), we get a palindrome (62460499406426).

The spelling of 31310245205113 in words is "thirty-one trillion, three hundred ten billion, two hundred forty-five million, two hundred five thousand, one hundred thirteen".

Divisors: 1 7 4472892172159 31310245205113