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3131043040433 = 711133993034771
BaseRepresentation
bin101101100100000000101…
…101010100110010110001
3102002022202202212110120002
4231210000231110302301
5402244334004243213
610354214210355345
7442132110502460
oct55440055246261
912068682773502
103131043040433
11aa79601965a0
12426997b8bb55
13199343831309
14ab786b149d7
15566a3e3b658
hex2d900b54cb1

3131043040433 has 16 divisors (see below), whose sum is σ = 3903930700800. Its totient is φ = 2439590907600.

The previous prime is 3131043040331. The next prime is 3131043040501. The reversal of 3131043040433 is 3340403401313.

It is not a de Polignac number, because 3131043040433 - 218 = 3131042778289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3131043040396 and 3131043040405.

It is not an unprimeable number, because it can be changed into a prime (3131043040033) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 485663 + ... + 2549108.

It is an arithmetic number, because the mean of its divisors is an integer number (243995668800).

Almost surely, 23131043040433 is an apocalyptic number.

It is an amenable number.

3131043040433 is a deficient number, since it is larger than the sum of its proper divisors (772887660367).

3131043040433 is a wasteful number, since it uses less digits than its factorization.

3131043040433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3048188.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 3131043040433 its reverse (3340403401313), we get a palindrome (6471446441746).

The spelling of 3131043040433 in words is "three trillion, one hundred thirty-one billion, forty-three million, forty thousand, four hundred thirty-three".

Divisors: 1 7 11 77 13399 93793 147389 1031723 3034771 21243397 33382481 233677367 40662896629 284640276403 447291862919 3131043040433