Base | Representation |
---|---|
bin | 101101100100000000101… |
… | …101010100110010110001 |
3 | 102002022202202212110120002 |
4 | 231210000231110302301 |
5 | 402244334004243213 |
6 | 10354214210355345 |
7 | 442132110502460 |
oct | 55440055246261 |
9 | 12068682773502 |
10 | 3131043040433 |
11 | aa79601965a0 |
12 | 426997b8bb55 |
13 | 199343831309 |
14 | ab786b149d7 |
15 | 566a3e3b658 |
hex | 2d900b54cb1 |
3131043040433 has 16 divisors (see below), whose sum is σ = 3903930700800. Its totient is φ = 2439590907600.
The previous prime is 3131043040331. The next prime is 3131043040501. The reversal of 3131043040433 is 3340403401313.
It is not a de Polignac number, because 3131043040433 - 218 = 3131042778289 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3131043040396 and 3131043040405.
It is not an unprimeable number, because it can be changed into a prime (3131043040033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 485663 + ... + 2549108.
It is an arithmetic number, because the mean of its divisors is an integer number (243995668800).
Almost surely, 23131043040433 is an apocalyptic number.
It is an amenable number.
3131043040433 is a deficient number, since it is larger than the sum of its proper divisors (772887660367).
3131043040433 is a wasteful number, since it uses less digits than its factorization.
3131043040433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3048188.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 3131043040433 its reverse (3340403401313), we get a palindrome (6471446441746).
The spelling of 3131043040433 in words is "three trillion, one hundred thirty-one billion, forty-three million, forty thousand, four hundred thirty-three".
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