Base | Representation |
---|---|
bin | 100011100110001011111000… |
… | …0011001010000111001001011 |
3 | 1112001122011100212222220120102 |
4 | 1013030113300121100321023 |
5 | 312020004214131002311 |
6 | 3025533224524320015 |
7 | 122644361320563434 |
oct | 10714276031207113 |
9 | 1461564325886512 |
10 | 313111444000331 |
11 | 908488aa381129 |
12 | 2b14b1190a300b |
13 | 105933897a31a2 |
14 | 574696372848b |
15 | 262eb31c7543b |
hex | 11cc5f0650e4b |
313111444000331 has 16 divisors (see below), whose sum is σ = 335315091552000. Its totient is φ = 291724129065600.
The previous prime is 313111444000309. The next prime is 313111444000379. The reversal of 313111444000331 is 133000444111313.
It is not a de Polignac number, because 313111444000331 - 210 = 313111443999307 is a prime.
It is a super-2 number, since 2×3131114440003312 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (29).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 313111444000294 and 313111444000303.
It is not an unprimeable number, because it can be changed into a prime (313111444000631) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 498667040 + ... + 499294541.
It is an arithmetic number, because the mean of its divisors is an integer number (20957193222000).
Almost surely, 2313111444000331 is an apocalyptic number.
313111444000331 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
313111444000331 is a deficient number, since it is larger than the sum of its proper divisors (22203647551669).
313111444000331 is a wasteful number, since it uses less digits than its factorization.
313111444000331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 997961990.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 313111444000331 its reverse (133000444111313), we get a palindrome (446111888111644).
The spelling of 313111444000331 in words is "three hundred thirteen trillion, one hundred eleven billion, four hundred forty-four million, three hundred thirty-one", and thus it is an aban number.
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