Base | Representation |
---|---|
bin | 101101100100001100101… |
… | …001110001100110100011 |
3 | 102002100021201221122012211 |
4 | 231210030221301212203 |
5 | 402300241304431301 |
6 | 10354250125502551 |
7 | 442140063026434 |
oct | 55441451614643 |
9 | 12070251848184 |
10 | 3131243436451 |
11 | aa7a5331a039 |
12 | 426a33111a57 |
13 | 1993761c6940 |
14 | ab7a559b48b |
15 | 566b6823051 |
hex | 2d90ca719a3 |
3131243436451 has 8 divisors (see below), whose sum is σ = 3549587701520. Its totient is φ = 2738253369312.
The previous prime is 3131243436437. The next prime is 3131243436463. The reversal of 3131243436451 is 1546343421313.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3131243436451 - 29 = 3131243435939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3131243436481) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6338549220 + ... + 6338549713.
It is an arithmetic number, because the mean of its divisors is an integer number (443698462690).
Almost surely, 23131243436451 is an apocalyptic number.
3131243436451 is a deficient number, since it is larger than the sum of its proper divisors (418344265069).
3131243436451 is a wasteful number, since it uses less digits than its factorization.
3131243436451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12677098965.
The product of its digits is 311040, while the sum is 40.
Adding to 3131243436451 its reverse (1546343421313), we get a palindrome (4677586857764).
The spelling of 3131243436451 in words is "three trillion, one hundred thirty-one billion, two hundred forty-three million, four hundred thirty-six thousand, four hundred fifty-one".
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