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31314044003 = 1120171411369
BaseRepresentation
bin11101001010011101…
…100110010001100011
32222211022220020212112
4131022131212101203
51003112343402003
622215132345535
72155663660634
oct351235462143
988738806775
1031314044003
1112309a63810
12609b0152ab
132c506a9528
141730b8388b
15c341903d8
hex74a766463

31314044003 has 8 divisors (see below), whose sum is σ = 34177735920. Its totient is φ = 28453178880.

The previous prime is 31314043967. The next prime is 31314044017. The reversal of 31314044003 is 30044041313.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31314044003 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 31314044003.

It is not an unprimeable number, because it can be changed into a prime (31314044053) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 683498 + ... + 727871.

It is an arithmetic number, because the mean of its divisors is an integer number (4272216990).

Almost surely, 231314044003 is an apocalyptic number.

31314044003 is a deficient number, since it is larger than the sum of its proper divisors (2863691917).

31314044003 is a wasteful number, since it uses less digits than its factorization.

31314044003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1413397.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 31314044003 its reverse (30044041313), we get a palindrome (61358085316).

The spelling of 31314044003 in words is "thirty-one billion, three hundred fourteen million, forty-four thousand, three".

Divisors: 1 11 2017 22187 1411369 15525059 2846731273 31314044003