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313144445035 = 562628889007
BaseRepresentation
bin1001000111010001101…
…11010000100001101011
31002221021120112000112201
410203220313100201223
520112304434220120
6355505004121031
731424003602462
oct4435067204153
91087246460481
10313144445035
1111089296a414
1250833536177
13236b6105c36
1411228b4b9d9
15822b64440a
hex48e8dd086b

313144445035 has 4 divisors (see below), whose sum is σ = 375773334048. Its totient is φ = 250515556024.

The previous prime is 313144444967. The next prime is 313144445051. The reversal of 313144445035 is 530544441313.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530544441313 = 665717969603.

It is a cyclic number.

It is not a de Polignac number, because 313144445035 - 227 = 313010227307 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 313144444985 and 313144445003.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31314444499 + ... + 31314444508.

It is an arithmetic number, because the mean of its divisors is an integer number (93943333512).

Almost surely, 2313144445035 is an apocalyptic number.

313144445035 is a deficient number, since it is larger than the sum of its proper divisors (62628889013).

313144445035 is an equidigital number, since it uses as much as digits as its factorization.

313144445035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62628889012.

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 313144445035 its reverse (530544441313), we get a palindrome (843688886348).

The spelling of 313144445035 in words is "three hundred thirteen billion, one hundred forty-four million, four hundred forty-five thousand, thirty-five".

Divisors: 1 5 62628889007 313144445035