Base | Representation |
---|---|
bin | 11101001011000001… |
… | …010101001111101001 |
3 | 2222211222112011120101 |
4 | 131023001111033221 |
5 | 1003122243131213 |
6 | 22220105225401 |
7 | 2156136414136 |
oct | 351301251751 |
9 | 88758464511 |
10 | 31323411433 |
11 | 12314281696 |
12 | 60a2192261 |
13 | 2c526091a2 |
14 | 173210158d |
15 | c34de0bdd |
hex | 74b0553e9 |
31323411433 has 4 divisors (see below), whose sum is σ = 31352879488. Its totient is φ = 31293943380.
The previous prime is 31323411377. The next prime is 31323411451. The reversal of 31323411433 is 33411432313.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 31323411433 - 221 = 31321314281 is a prime.
It is a super-2 number, since 2×313234114332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31323421433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14732433 + ... + 14734558.
It is an arithmetic number, because the mean of its divisors is an integer number (7838219872).
Almost surely, 231323411433 is an apocalyptic number.
It is an amenable number.
31323411433 is a deficient number, since it is larger than the sum of its proper divisors (29468055).
31323411433 is a wasteful number, since it uses less digits than its factorization.
31323411433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29468054.
The product of its digits is 7776, while the sum is 28.
Adding to 31323411433 its reverse (33411432313), we get a palindrome (64734843746).
The spelling of 31323411433 in words is "thirty-one billion, three hundred twenty-three million, four hundred eleven thousand, four hundred thirty-three".
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