3133014121 has 4 divisors (see below), whose sum is σ = 3133960272. Its totient is φ = 3132067972.

The previous prime is 3133014119. The next prime is 3133014149. The reversal of 3133014121 is 1214103313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3133014121 - 2¹ = 3133014119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3133014151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468091 + ... + 474736.

It is an arithmetic number, because the mean of its divisors is an integer number (783490068).

Almost surely, 2^3133014121 is an apocalyptic number.

It is an amenable number.

3133014121 is a deficient number, since it is larger than the sum of its proper divisors (946151).

3133014121 is an equidigital number, since it uses as much as digits as its factorization.

3133014121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 946150.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 3133014121 is about 55973.3340171907. The cubic root of 3133014121 is about 1463.2575852998.

Adding to 3133014121 its reverse (1214103313), we get a palindrome (4347117434).

It can be divided in two parts, 31330 and 14121, that added together give a triangular number (45451 = T₃₀₁).

The spelling of 3133014121 in words is "three billion, one hundred thirty-three million, fourteen thousand, one hundred twenty-one".