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3133052144401 = 4176415905961
BaseRepresentation
bin101101100101111000011…
…101011100101100010001
3102002111221210100112002011
4231211320131130230101
5402312442322110101
610355145420422521
7442232644552444
oct55457035345421
912074853315064
103133052144401
11aa87a12910a3
124272589a7a41
131995a3b4542a
14ab8d789d65b
15567704eb751
hex2d97875cb11

3133052144401 has 4 divisors (see below), whose sum is σ = 3209468050404. Its totient is φ = 3056636238400.

The previous prime is 3133052144393. The next prime is 3133052144429. The reversal of 3133052144401 is 1044412503313.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1230156047376 + 1902896097025 = 1109124^2 + 1379455^2 .

It is a cyclic number.

It is not a de Polignac number, because 3133052144401 - 23 = 3133052144393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3133052144501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38207952940 + ... + 38207953021.

It is an arithmetic number, because the mean of its divisors is an integer number (802367012601).

Almost surely, 23133052144401 is an apocalyptic number.

It is an amenable number.

3133052144401 is a deficient number, since it is larger than the sum of its proper divisors (76415906003).

3133052144401 is an equidigital number, since it uses as much as digits as its factorization.

3133052144401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76415906002.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 3133052144401 its reverse (1044412503313), we get a palindrome (4177464647714).

The spelling of 3133052144401 in words is "three trillion, one hundred thirty-three billion, fifty-two million, one hundred forty-four thousand, four hundred one".

Divisors: 1 41 76415905961 3133052144401